7p^2-192p-208=0

Solution for 7p^2-192p-208=0 equation:

7p^2-192p-208=0

a = 7; b = -192; c = -208;
Δ = b2-4ac
Δ = -1922-4·7·(-208)
Δ = 42688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{42688}=\sqrt{64*667}=\sqrt{64}*\sqrt{667}=8\sqrt{667}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-8\sqrt{667}}{2*7}=\frac{192-8\sqrt{667}}{14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+8\sqrt{667}}{2*7}=\frac{192+8\sqrt{667}}{14}
$